-2[3(x-5)-2(3x+2)]=10

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Solution for -2[3(x-5)-2(3x+2)]=10 equation:


Simplifying
-2[3(x + -5) + -2(3x + 2)] = 10

Reorder the terms:
-2[3(-5 + x) + -2(3x + 2)] = 10
-2[(-5 * 3 + x * 3) + -2(3x + 2)] = 10
-2[(-15 + 3x) + -2(3x + 2)] = 10

Reorder the terms:
-2[-15 + 3x + -2(2 + 3x)] = 10
-2[-15 + 3x + (2 * -2 + 3x * -2)] = 10
-2[-15 + 3x + (-4 + -6x)] = 10

Reorder the terms:
-2[-15 + -4 + 3x + -6x] = 10

Combine like terms: -15 + -4 = -19
-2[-19 + 3x + -6x] = 10

Combine like terms: 3x + -6x = -3x
-2[-19 + -3x] = 10
[-19 * -2 + -3x * -2] = 10
[38 + 6x] = 10

Solving
38 + 6x = 10

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-38' to each side of the equation.
38 + -38 + 6x = 10 + -38

Combine like terms: 38 + -38 = 0
0 + 6x = 10 + -38
6x = 10 + -38

Combine like terms: 10 + -38 = -28
6x = -28

Divide each side by '6'.
x = -4.666666667

Simplifying
x = -4.666666667

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